Dear all, I should like to ask you whether anyone of you is willing to share information about the complex refractive index of PEDOT:PSS. I am in Indonesia and am conducting my research on optical modelling for Organic Photovoltaic Devices in Gadjah Mada University. Unfortunately, the facilities here is not sufficient to conduct the measurement of the complex refractive index since we do not have the apparatus. I would be very happy if anyone of you can help me overcoming the difficulty I meet here.
Hello Timothy and welcome to RefractiveIndex.INFO forum! Unfortunately, the forum is quite new and there are only few members so far... I hope, however, that you will be able to find the required information. If so, please share it with me so I can add it to the database. Thanks!
Hi Shmulik, According to "Handbook of Optical Materials", liquids with highest refractive indexes are nitrobenzene (nd=1.5562), bromobenzene (nd=1.5597), 1–methylnaphthalene (nd=1.6170) and carbon disulfide (nd=1.6319). If you need a liquid with a higher or a specific value of refractive index, you can check commercial optical liquids. For example Cargille sells liquids with index of refraction up to 2.3 ( see http://cargille.com/opticalintro.shtml ). Regards!
Hi, I'm a physics sophomore. I am looking for information about the highest refraction index (within visible light scope and in general) that has ever been detected/obtained in any substance in any temperature range. Can you suggest any sources to get this info? Thanks.
Can any one give me an experssion of refractive index as a function of wavelength and temperature for acrylic or glass or any thermooptic material. Thanks in advanced
Hi, I'm researching physics for the summer, and I was wondering if there is a way of determining the optical penetration depth and reflectivity for different metals from values of n and k. I see that the site calculates reflectivity coefficients from these two values, but how is that done, and does anyone know the similar calculation for depth?
reflectivity is calculated form refractive index using Fresnel equations: http://en.wikipedia.org/wiki/Fresnel_equations. Just have in mind that in the case of non-zero k you should use complex refractive index (n+ik) in all formulas.
Hi, I'm looking for extinction coefficient (imaginary part 'k' of complex refractive index N=n+i*k) of H2O and D2O at lambda0=1064nm (or a visible--NIR spectrum) under normal temperature and pressure. Several days searching on internet without success makes me sorrowful. Please can anybody help me? Thanks in advanced.
Hi Honza3, try search for "absorption coefficient" - it should be easier to find. Then use this forormula to calculate k: alpha = 4*pi*k/lambda (here alpha is absorption coefficient)
I am a PhD student in Switzerland. I need to manufacture a tube with special material to be transparent and have the Reflective index close to water. I mean between 1.33 to 1.42. I will do some PIV (visualization work). I need a material to manufacture a tube with curved geometry, not a straight one. Do you have any suggestion?
Moreover, Is there any special fluid with high Reflective index (say 1.5) and low viscosity (say 3cp) to use as a working fluid in a plexi-glass tube?
sounds like a tough task: solids are generally more optically dense than liquids. CaF2 has refractive index slightly higher than 1.42, but I don't think it is feasible for your application... Try to take a look on index matching liquids ( http://www.cargille.com/products.shtmlhttp://www.cargille.com/specimmerliq.shtml ) although I am afraid that they could have quite high viscosity
Hello, I was looking up the refractive indices of potassium niobate, but the site does not specify the unit cell setup. I'm assuming it is X~3.9, Y~5.69, Z~5.70, or is it on the pseudocubic 4x4x4 angstrom perovskite setting?
Hello Dan, the data are for orthorhombic KNbO3: X(a) = 5.6896 Å, Y(b) = 3.9692 Å, and Z(c) = 5.7256 Å See the original publication for details: http://dx.doi.org/10.1364/JOSAB.9.000380
kindly provide me the information that : why in your database refractive index for Mgf2 start from 200 nm wavelength as its tranmission range starts from 120 nm.....is this material is a bifringe material---which index 9ordinary or extraordinary) to chose for the 121.6 nm transmission. why in lithium flouride c1,c2,c3 , c4 value has ben taken in place of a1,a2,a3,a4---and what is the exact method to find out these constants... if possible , provide me the list of such mateial who capable to tranmit 121.6 nm eg MgF2.LiF or more.
what reference wavelength i can take to transmit 121.6 nm ......
hi faisalngo, I included the reference on the original papers for both materials you are interested in (see bottom of the pages) http://refractiveindex.info/?group=CRYSTALS&material=MgF2 http://refractiveindex.info/?group=CRYSTALS&material=LiF hopefully you can find more information there. Please let me know if you will find data for MgF2 refractive index for broader range. choice between O and E depends on the light polarization and crystal orientation I don't see a problem in using C instead of A for dispersion formula coefficients. Do you have any concerns? Please refer to the papers for the methods sorry, I cannot provide such a list... maybe someone else here? sorry, I did not get the last question
dear sir , thanks to provide me a valuable information--- some of my queries---is magnesium flouride a crystal----its substrate is available or not----is it bifringe material-------is the mgf2 plates are available ......
dear sir how to find out dn/dlambda-----what parameters have to take out------i m looking for such material who capable to transmit EUV like from 1200 A/lower to whatever the maximum wavelength----like MgF2,LiF ----so please advise me for other materials also if possible----is MgF2 and LiF is absorbing in nature-----is the K value for both these materials is 0------ also how i can use these materials to design 1216 A bandpass filter with bandgap of 100 angstro or lower----kindly suggest me some papers for bandpass filter design for the EUV transmission ( in between 120 to 150 nm) by using mgF2/LiF or any other material....i will be thankful to you.....
hi faisalngo, sorry, but I did not feel like explaining derivatives... Try to take a look at http://en.wikipedia.org/wiki/Derivative And unfortunately I don't have any knowledge about designing bandpass filters. Hopefully someone else on this forum can help you with that...
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